2^m+1=16^m+7

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Solution for 2^m+1=16^m+7 equation: 



2^m+1=16^m+7

We move all terms to the left:

2^m+1-(16^m+7)=0

We get rid of parentheses

2^m-16^m-7+1=0

We add all the numbers together, and all the variables

2^m-16^m-6=0

We move all terms containing m to the left, all other terms to the right

2^m-16^m=6

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